MHT CET · Maths · Application of Derivatives
If \(x\) is real, then the difference between the greatest and least values of \(\frac{x^2-x+1}{x^2+x+1}\) is
- A \(\frac{10}{3}\)
- B \(\frac{8}{3}\)
- C \(\frac{5}{3}\)
- D \(\frac{1}{3}\)
Answer & Solution
Correct Answer
(B) \(\frac{8}{3}\)
Step-by-step Solution
Detailed explanation
Let \(y = \frac{x^2-x+1}{x^2+x+1}\). \((y-1)x^2 + (y+1)x + (y-1) = 0\)
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