MHT CET · Maths · Differential Equations
If \(x \frac{\mathrm{dy}}{\mathrm{d} x}=\mathrm{y}(\log \mathrm{y}-\log x+1)\), then the solution of the equation is
- A \(\log \frac{x}{\mathrm{y}}=\mathrm{cy}\), where c is the constant of integration
- B \(\log \frac{\mathrm{y}}{x}=\mathrm{cy}\), where c is the constant of integration
- C \(\log \frac{x}{\mathrm{y}}=\mathrm{c} x\), where c is the constant of integration
- D \(\log \frac{\mathrm{y}}{x}=\mathrm{c} x\), where c is the constant of integration
Answer & Solution
Correct Answer
(D) \(\log \frac{\mathrm{y}}{x}=\mathrm{c} x\), where c is the constant of integration
Step-by-step Solution
Detailed explanation
\(x \frac{\mathrm{dy}}{\mathrm{d} x}=\mathrm{y}\left(\log \left(\frac{\mathrm{y}}{x}\right)+1\right)\) Let \(\mathrm{y}=vx \implies \frac{\mathrm{dy}}{\mathrm{d} x}=v+x \frac{\mathrm{dv}}{\mathrm{d} x}\)
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