MHT CET · Maths · Probability
If \(\quad X \sim B(n, p)\) then \(\frac{P(X=k)}{P(X=k-1)}=\)
- A \(\frac{\mathrm{n}-\mathrm{k}}{\mathrm{k}-1} \cdot \frac{\mathrm{p}}{\mathrm{q}}\)
- B \(\frac{\mathrm{n}-\mathrm{k}+1}{\mathrm{k}+1} \cdot \frac{\mathrm{p}}{\mathrm{q}}\)
- C \(\frac{\mathrm{n}+1}{\mathrm{k}} \cdot \frac{\mathrm{q}}{\mathrm{p}}\)
- D \(\frac{\mathrm{n}-\mathrm{k}+1}{\mathrm{k}} \cdot \frac{\mathrm{p}}{\mathrm{q}}\)
Answer & Solution
Correct Answer
(D) \(\frac{\mathrm{n}-\mathrm{k}+1}{\mathrm{k}} \cdot \frac{\mathrm{p}}{\mathrm{q}}\)
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