MHT CET · Maths · Differentiation
If \(u_{0}=8, u_{1}=3, u_{2}=12, u_{3}=51\), then the value of \(\Delta^{3} u_{0}\) is
- A 12
- B 14
- C 16
- D 18
Answer & Solution
Correct Answer
(C) 16
Step-by-step Solution
Detailed explanation
\(\Delta^{3} u_{0}=(E-1)^{3} u_{0}\)
\(=\left(E^{3}-3 E^{2}+3 E-1\right) u_{0}=u_{3}-3 u_{2}+3 u_{1}-u_{0} \)
\( =51-3 \times 12+3 \times 3-8=16\)
\(=\left(E^{3}-3 E^{2}+3 E-1\right) u_{0}=u_{3}-3 u_{2}+3 u_{1}-u_{0} \)
\( =51-3 \times 12+3 \times 3-8=16\)
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