MHT CET · Maths · Application of Derivatives
If two curves \(x^2-4 y^2=2\) and \(8 x^2=40-\mathrm{my}^2\) are orthogonal to each other then \(\mathrm{m}=\)
- A \(2\)
- B \(16\)
- C \(\frac{1}{\sqrt{2}}\)
- D \(4\)
Answer & Solution
Correct Answer
(B) \(16\)
Step-by-step Solution
Detailed explanation
\(x^2 - 4y^2 = 2 \implies 2x - 8y \frac{dy}{dx} = 0 \implies \frac{dy}{dx}_1 = \frac{x}{4y}\) \(8x^2 + my^2 = 40 \implies 16x + 2my \frac{dy}{dx} = 0 \implies \frac{dy}{dx}_2 = -\frac{8x}{my}\)
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