MHT CET · Maths · Quadratic Equation
If triangle \(A B C\) is a right angled at \(A\) and \(\tan \frac{B}{2}, \tan \frac{C}{2}\) are roots of the equation \(a x^2+b x+c=0, a \neq 0\), then
- A \(a+c=b\)
- B \(a+b=c\)
- C \(\mathrm{b}+\mathrm{c}=a\)
- D \(a+c=2 b\)
Answer & Solution
Correct Answer
(B) \(a+b=c\)
Step-by-step Solution
Detailed explanation
\(A = 90^\circ \implies B+C = 90^\circ \implies \frac{B}{2} + \frac{C}{2} = 45^\circ\) \(\tan\left(\frac{B}{2} + \frac{C}{2}\right) = \tan 45^\circ = 1\)
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