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MHT CET · Maths · Vector Algebra

If the vectors \(\overline{\mathrm{AB}}=3 \hat{\mathrm{i}}+4 \hat{\mathrm{k}}\) and \(\overline{\mathrm{AC}}=5 \hat{\mathrm{i}}-2 \hat{\mathrm{j}}+4 \hat{\mathrm{k}}\) are the sides of the triangle \(A B C\), then the length of the median through A is

  1. A \(\sqrt{45}\) units
  2. B \(\sqrt{18}\) units
  3. C \(\sqrt{72}\) units
  4. D \(\sqrt{33}\) units
Verified Solution

Answer & Solution

Correct Answer

(D) \(\sqrt{33}\) units

Step-by-step Solution

Detailed explanation

Let \(A D\) be the median of \(\triangle A B C\).
\(\begin{aligned}
\overline{\mathrm{AD}} & =\frac{\overline{\mathrm{AB}}+\overline{\mathrm{AC}}}{2} \\
& =\frac{8 \hat{\mathrm{i}}-2 \hat{\mathrm{j}}+8 \hat{\mathrm{k}}}{2} \\
& =4 \hat{\mathrm{i}}-\hat{\mathrm{j}}+4 \hat{\mathrm{k}}
\end{aligned}\)
\(\therefore|\overline{\mathrm{AD}}|=\sqrt{4^2+1^2+4^2}=\sqrt{33}\) units