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MHT CET · Maths · Vector Algebra

If the vectors \(\overline{\mathrm{a}}=\hat{\mathrm{i}}-\hat{\mathrm{j}}+2 \hat{\mathrm{k}}, \overline{\mathrm{b}}=2 \hat{\mathrm{i}}+4 \hat{\mathrm{j}}+\hat{\mathrm{k}}\) and \(\overline{\mathrm{c}}=\lambda \hat{\mathrm{i}}+\hat{\mathrm{j}}+\mu \hat{\mathrm{k}}\) are mutually orthogonal, then \((\lambda, \mu) \equiv\)

  1. A \((-3,2)\)
  2. B \((-2,3)\)
  3. C \((2,-3)\)
  4. D \((3,-2)\)
Verified Solution

Answer & Solution

Correct Answer

(A) \((-3,2)\)

Step-by-step Solution

Detailed explanation

As vectors \(\overline{\mathrm{a}}, \overline{\mathrm{b}}, \overline{\mathrm{c}}\) are mutually orthogonal, we get
\(\overline{\mathrm{a}} \cdot \overline{\mathrm{c}}=0 \)
\( \therefore \lambda-1+2 \mu=0 \)
\( \therefore \lambda+2 \mu=1...(i)\)
and \(\bar{b} \cdot \bar{c}=0\)
\(\therefore 2 \lambda+4+\mu=0 \)
\( \therefore 2 \lambda+\mu=-4...(ii)\)
Solving (i) and (ii), we get
\(\lambda=-3, \mu=2\)