MHT CET · Maths · Vector Algebra
If the vectors \(2 \hat{i}-3 \hat{j}+6 \hat{k}\) and \(\bar{b}\) are collinear and \(|\bar{b}|=14\), then \(\bar{b}\) has the value
- A \(4 \hat{i}+6 \hat{j}+12 \hat{k}\)
- B \(-4 \hat{i}-6 \hat{j}-12 \hat{k}\)
- C \(4 \hat{i}-6 \hat{j}+12 \hat{k}\)
- D \(12 \hat{i}+5 \hat{j}+\sqrt{17} \widehat{k}\)
Answer & Solution
Correct Answer
(C) \(4 \hat{i}-6 \hat{j}+12 \hat{k}\)
Step-by-step Solution
Detailed explanation
\(\vec{b}=14\left(\frac{2 \hat{i}-3 \hat{j}+6 \hat{k}}{\sqrt{2^2+(-3)^2+6^2}}\right)=14\left(\frac{2 \hat{i}-3 \hat{j}+6 \hat{k}}{7}\right)=4 \hat{i}-6 \hat{j}+12 \hat{k}\)
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