MHT CET · Maths · Circle
If the tangent and the normal at the point \((\sqrt{3}, 1)\) to the circle \(x^2+\mathrm{y}^2=4\), and the X -axis form a triangle, then the area (in sq.units) of this triangle is
- A \(\frac{1}{\sqrt{2}}\)
- B \(\frac{2}{\sqrt{3}}\)
- C \(\frac{4}{\sqrt{3}}\)
- D \(\frac{1}{3}\)
Answer & Solution
Correct Answer
(B) \(\frac{2}{\sqrt{3}}\)
Step-by-step Solution
Detailed explanation
Tangent equation: \(x x_1 + y y_1 = r^2\) \(x(\sqrt{3}) + y(1) = 4\)
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