MHT CET · Maths · Three Dimensional Geometry
If the sum of the squares of the distance of the point \(\mathrm{P}(\mathrm{x}, \mathrm{y}, \mathrm{z})\) from the co-ordinate axes is 242 , then the distance of the point \(P\) from the origin is _______ units.
- A \(121\)
- B \(11\)
- C \(22\)
- D \(\frac{121}{2}\)
Answer & Solution
Correct Answer
(B) \(11\)
Step-by-step Solution
Detailed explanation
\( (\sqrt{y^2+z^2})^2 + (\sqrt{x^2+z^2})^2 + (\sqrt{x^2+y^2})^2 = 242 \) \( y^2+z^2+x^2+z^2+x^2+y^2 = 242 \)
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