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MHT CET · Maths · Circle

If the radius of a circle \(x^{2}+y^{2}-4 x+6 y-k=0\) is 5, then \(\mathrm{k}=\)

  1. A \(-12\)
  2. B \(-25\)
  3. C \(25\)
  4. D \(12\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(12\)

Step-by-step Solution

Detailed explanation

Given equation of circle is
\(
\begin{array}{l}
x^{2}+y^{2}-4 x+6 y-k=0 \\
r \quad=\sqrt{4+9+k} \Rightarrow 5=\sqrt{13+k} \Rightarrow 13+k=25 \\
k=12
\end{array}
\)