MHT CET · Maths · Pair of Lines
If the pair of lines \(3 x^2-5 x y+p y^2=0\) and \(6 x^2-x y-5 y^2=0\) have one line common, then \(\mathrm{p}=\)
- A \(2, \frac{25}{4}\)
- B \(-2, \frac{25}{4}\)
- C \(2, \frac{-25}{4}\)
- D \(-2, \frac{-25}{4}\)
Answer & Solution
Correct Answer
(C) \(2, \frac{-25}{4}\)
Step-by-step Solution
Detailed explanation
\( p(y/x)^2 - 5(y/x) + 3 = 0 \) \( -5(y/x)^2 - (y/x) + 6 = 0 \)
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