MHT CET · Maths · Probability
If the p.m.f. of a discrete random variable \(X\) is \(P(X=x)=\frac{c}{x^3}\), \(x=1,2,3=0\), otherwise then \(E(X)\) is equal to
- A \(\frac{297}{294}\)
- B \(\frac{249}{225}\)
- C \(\frac{343}{297}\)
- D \(\frac{294}{251}\)
Answer & Solution
Correct Answer
(D) \(\frac{294}{251}\)
Step-by-step Solution
Detailed explanation

\(\begin{aligned} & \because \sum P_i=1 \\ & \Rightarrow \frac{251}{216} C \\ & \Rightarrow C=\frac{216}{251} \\ & \text { now } E(x)=\sum p_i x_i=\frac{49}{36} C=\frac{49}{36} \times \frac{216}{251}=\frac{294}{251}\end{aligned}\)
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