MHT CET · Maths · Three Dimensional Geometry
If the lines \(\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{4}\) and \(\frac{x-3}{1}=\frac{y-k}{2}=\frac{z}{1}\) intersect, then \(k=\)
- A \(\frac{9}{2}\)
- B \(\frac{2}{9}\)
- C \(\frac{-9}{2}\)
- D \(\frac{-2}{9}\)
Answer & Solution
Correct Answer
(A) \(\frac{9}{2}\)
Step-by-step Solution
Detailed explanation
Given two lines intersect. Thus shortest distance between them is zero.
Let \(\left(x_{1}, y_{1}, z_{1}\right) \equiv(1,-1,1)\) and \(\left(x_{2}, y_{2}, z_{2}\right) \equiv(3, k, 0)\)
Let \(\left(x_{1}, y_{1}, z_{1}\right) \equiv(1,-1,1)\) and \(\left(x_{2}, y_{2}, z_{2}\right) \equiv(3, k, 0)\)
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