MHT CET · Maths · Three Dimensional Geometry
If the lines \(\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{4}\) and \(\frac{x-2}{1}=\frac{y+m}{2}=\frac{z-2}{1}\) intersect each other, then value of \(m\) is
- A 1
- B -2
- C 2
- D -1
Answer & Solution
Correct Answer
(D) -1
Step-by-step Solution
Detailed explanation
Two intersection lines are
\(\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{4}=\lambda \text { and } \frac{x-2}{1}=\frac{y+m}{2}=\frac{z-2}{1}=\mu\)
From (1) and (2) \(\lambda=0\) and \(\mu=-1\) Then from (3), we get \(m=-1\)
\(\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{4}=\lambda \text { and } \frac{x-2}{1}=\frac{y+m}{2}=\frac{z-2}{1}=\mu\)
From (1) and (2) \(\lambda=0\) and \(\mu=-1\) Then from (3), we get \(m=-1\)
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