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MHT CET · Maths · Three Dimensional Geometry

If the line \(\frac{x-3}{2}=\frac{y+5}{-1}=\frac{z+2}{2}\) lies in the plane \(\alpha x+3 y-z+\beta=0\), then values of \(\alpha\) and \(\beta\) respectively are ....

  1. A \(\frac{3}{2}, \frac{13}{2}\)
  2. B \(\frac{5}{2}, \frac{9}{2}\)
  3. C \(-\frac{5}{2}, \frac{9}{2}\)
  4. D \(\frac{5}{2}, \frac{11}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{5}{2}, \frac{11}{2}\)

Step-by-step Solution

Detailed explanation

\( \vec{d} = (2, -1, 2) \) \( \vec{n} = (\alpha, 3, -1) \)