MHT CET · Maths · Three Dimensional Geometry
If the line \(\frac{x-3}{2}=\frac{y+5}{-1}=\frac{z+2}{2}\) lies in the plane \(\alpha x+3 y-z+\beta=0\), then values of \(\alpha\) and \(\beta\) respectively are ....
- A \(\frac{3}{2}, \frac{13}{2}\)
- B \(\frac{5}{2}, \frac{9}{2}\)
- C \(-\frac{5}{2}, \frac{9}{2}\)
- D \(\frac{5}{2}, \frac{11}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{5}{2}, \frac{11}{2}\)
Step-by-step Solution
Detailed explanation
\( \vec{d} = (2, -1, 2) \) \( \vec{n} = (\alpha, 3, -1) \)
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