MHT CET · Maths · Three Dimensional Geometry
If the line \(\frac{x+1}{1}=\frac{y-k}{11}=\frac{z-4}{-5}\) lies in the plane \(2 x+p y+7 z-41=0\) which is perpendicular to the plane \(x+4 \mathrm{y}-2 \mathrm{z}+13=0\) then \(\mathrm{k}=\)
- A \(3\)
- B \(-3\)
- C \(-5\)
- D 5
Answer & Solution
Correct Answer
(D) 5
Step-by-step Solution
Detailed explanation
\(2(1) + p(4) + 7(-2) = 0\) \(2 + 4p - 14 = 0\)
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