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MHT CET · Maths · Three Dimensional Geometry

If the line \(\frac{x+1}{1}=\frac{y-k}{11}=\frac{z-4}{-5}\) lies in the plane \(2 x+p y+7 z-41=0\) which is perpendicular to the plane \(x+4 \mathrm{y}-2 \mathrm{z}+13=0\) then \(\mathrm{k}=\)

  1. A \(3\)
  2. B \(-3\)
  3. C \(-5\)
  4. D 5
Verified Solution

Answer & Solution

Correct Answer

(D) 5

Step-by-step Solution

Detailed explanation

\(2(1) + p(4) + 7(-2) = 0\) \(2 + 4p - 14 = 0\)