MHT CET · Maths · Straight Lines
If the line through the points \((-2,6)\) and \((4,8)\) is perpendicular to the line passing through the points \((8,12)\) and \((x, 24)\), then the value of \(x\) is
- A \(4\)
- B \(\frac{1}{3}\)
- C \(12\)
- D \(-2\)
Answer & Solution
Correct Answer
(A) \(4\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{m}_1 \times \mathrm{m}_2=-1 \Rightarrow \frac{8-6}{4+2}=\frac{24-12}{\mathrm{x}-8} \\ & \Rightarrow \frac{2}{6} \times \frac{12}{\mathrm{x}-8}=-1 \\ & \Rightarrow 4=-\mathrm{x}+8 \\ & \Rightarrow \mathrm{x}=4\end{aligned}\)
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