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MHT CET · Maths · Vector Algebra

If the lengths of three vectors \(\bar{a}, \overline{\mathrm{~b}}\) and \(\overline{\mathrm{c}}\) are 5,12,13 units respectively, and each one is perpendicular to the sum of the other two, then \(|\bar{a}+\overline{\mathrm{b}}+\overline{\mathrm{c}}|=\ldots \ldots\)

  1. A \(\sqrt{338}\)
  2. B \(169\)
  3. C \(338\)
  4. D \(676\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\sqrt{338}\)

Step-by-step Solution

Detailed explanation

\(|\bar{a}+\overline{\mathrm{b}}+\overline{\mathrm{c}}|^2 = |\bar{a}|^2 + |\overline{\mathrm{b}}|^2 + |\overline{\mathrm{c}}|^2\) (since each vector is perpendicular to the sum of the other two, implying \(2(\bar{a} \cdot \overline{\mathrm{b}} + \overline{\mathrm{b}} \cdot \overline{\mathrm{c}} + \overline{\mathrm{c}} \cdot \bar{a}) = 0\)) \(|\bar{a}+\overline{\mathrm{b}}+\overline{\mathrm{c}}|^2 = 5^2 + 12^2 + 13^2\)