MHT CET · Maths · Three Dimensional Geometry
If the foot of the perpendicular drawn from the origin to a plane is \(\mathrm{P}(2,-1,4)\), then the equation of the plane is
- A \(2 x+y+4 z-19=0\)
- B \(x+y+z-5=0\)
- C \(2 x-2 y-3 z+6=0\)
- D \(2 x-y+4 z-21=0\)
Answer & Solution
Correct Answer
(D) \(2 x-y+4 z-21=0\)
Step-by-step Solution
Detailed explanation
Normal vector \(\vec{n}\) is \((2, -1, 4)\). Equation of plane: \(a(x - x_1) + b(y - y_1) + c(z - z_1) = 0\)
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