MHT CET · Maths · Straight Lines
If the equation of the median through vertex \(A(3, k)\) of \(\triangle A B C\) with vertices \(\mathrm{B}(2,1)\) and \(\mathrm{C}(-4,5)\) is \(x+4 \mathrm{y}=\mathrm{p}\), then \(\mathrm{k}=\) where p and k are constants
- A \(1\)
- B \(2\)
- C \(-2\)
- D \(3\)
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
\(M = \left(\frac{2+(-4)}{2}, \frac{1+5}{2}\right) = (-1, 3)\) \(M\) lies on \(x+4y=p\): \(-1+4(3) = p \Rightarrow p = 11\)
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