MHT CET · Maths · Application of Derivatives
If the curves \(y^2=6 x\) and \(9 x^2+\) by \(^2=16\) intersect each other at right angles, then the value of b is
- A \(4\)
- B \(\frac{7}{2}\)
- C \(6\)
- D \(\frac{9}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{9}{2}\)
Step-by-step Solution
Detailed explanation
\(y^2=6x \implies 2y\frac{dy}{dx} = 6 \implies m_1 = \frac{3}{y}\) \(9x^2+by^2=16 \implies 18x+2by\frac{dy}{dx}=0 \implies m_2 = -\frac{9x}{by}\)
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