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MHT CET · Maths · Application of Derivatives

If the curve \(y=a x^2-6 x+b\) passes through \((0,4)\) and has its tangent parallel to the x -axis at \(x=\frac{3}{2}\), then the value of \(a\) and b respectively are

  1. A \(-2,-4\)
  2. B 2, 4
  3. C \(-2,4\)
  4. D \(2,-4\)
Verified Solution

Answer & Solution

Correct Answer

(B) 2, 4

Step-by-step Solution

Detailed explanation

\(4 = a(0)^2 - 6(0) + b \Rightarrow b=4\) \(\frac{dy}{dx} = 2ax - 6\)