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MHT CET · Maths · Mathematical Reasoning

If \(\{(p \wedge \sim q) \wedge(p \wedge r)\} \rightarrow \sim p \vee q\) has truth value false then truth values of the statements p, q, r are respectively

  1. A \(\mathrm{T}, \mathrm{T}, \mathrm{T}\)
  2. B \(\mathrm{F}, \mathrm{F}, \mathrm{F}\)
  3. C \(\mathrm{F}, \mathrm{F}, \mathrm{T}\)
  4. D \(\mathrm{T}, \mathrm{F}, \mathrm{T}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\mathrm{T}, \mathrm{F}, \mathrm{T}\)

Step-by-step Solution

Detailed explanation

\( \{ (p \wedge \sim q) \wedge (p \wedge r) \} \rightarrow (\sim p \vee q) \) is False \( \{ (p \wedge \sim q) \wedge (p \wedge r) \} \) is True AND \( (\sim p \vee q) \) is False.