MHT CET · Maths · Mathematical Reasoning
If p, \(q\) are true statement and \(\mathrm{r}\) is false statement, then which of the following atements is a true statement.
- A \((p \wedge q) \rightarrow r\) is true
- B \((p \rightarrow r) \rightarrow q\) is false
- C \((p \vee q) \vee r\) is false
- D \((p \leftrightarrow q) \leftrightarrow r\) is false.
Answer & Solution
Correct Answer
(D) \((p \leftrightarrow q) \leftrightarrow r\) is false.
Step-by-step Solution
Detailed explanation
\((\mathrm{A})\)
We have \(\mathrm{p} \equiv \mathrm{T}, \mathrm{q} \equiv \mathrm{T}\) and \(\mathrm{r} \equiv \mathrm{F}\)
We will check truth value of each option.
(A) \((\mathrm{p} \leftrightarrow \mathrm{q}) \leftrightarrow \mathrm{r}\)
\(\equiv(T \leftrightarrow T) \leftrightarrow F \equiv T \leftrightarrow F \equiv F\)
(B) \((p \vee q) \vee r\)
\(\equiv(T \vee T) \vee F \equiv T \vee F=T\)
(C) \((p \wedge q) \rightarrow r\)
\(\equiv(\mathrm{T} \wedge \mathrm{T}) \rightarrow \mathrm{F} \equiv \mathrm{T} \rightarrow \mathrm{F} \equiv \mathrm{F}\)
(D) \((\mathrm{p} \rightarrow \mathrm{r}) \rightarrow \mathrm{q}\)
\(\equiv(T \rightarrow F) \rightarrow T \equiv F \rightarrow T \equiv T\)
We have \(\mathrm{p} \equiv \mathrm{T}, \mathrm{q} \equiv \mathrm{T}\) and \(\mathrm{r} \equiv \mathrm{F}\)
We will check truth value of each option.
(A) \((\mathrm{p} \leftrightarrow \mathrm{q}) \leftrightarrow \mathrm{r}\)
\(\equiv(T \leftrightarrow T) \leftrightarrow F \equiv T \leftrightarrow F \equiv F\)
(B) \((p \vee q) \vee r\)
\(\equiv(T \vee T) \vee F \equiv T \vee F=T\)
(C) \((p \wedge q) \rightarrow r\)
\(\equiv(\mathrm{T} \wedge \mathrm{T}) \rightarrow \mathrm{F} \equiv \mathrm{T} \rightarrow \mathrm{F} \equiv \mathrm{F}\)
(D) \((\mathrm{p} \rightarrow \mathrm{r}) \rightarrow \mathrm{q}\)
\(\equiv(T \rightarrow F) \rightarrow T \equiv F \rightarrow T \equiv T\)
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