MHT CET · Maths · Probability
If \(P^{\prime}\left(A^{\prime}\right)+P\left(B^{\prime}\right) P(A \cup B)=0.7\) then \(P^{\prime}\left(A^{\prime}\right)+P\left(B^{\prime}\right)\) is
- A \(1.1\)
- B \(0.6\)
- C \(1.8\)
- D \(1.6\)
Answer & Solution
Correct Answer
(A) \(1.1\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & P\left(A^{\prime}\right)+P\left(B^{\prime}\right)=1-P(A)+1-P(B) \\ & =2-\{P(A)+P(B)\} \\ & =2-\{P(A \cup B)+P(A \cap B)\} \\ & =2-\{0.7+0.2\} \\ & =2-0.9 \\ & =1.1\end{aligned}\)
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