MHT CET · Maths · Circle
If one of the diameters of the circle, given by the equation \(x^2+y^2-4 x+6 y-12=0\), is a chord of a circle, 'S', whose centre is at \((-3,2)\), then the length of radius of ' \(S\) ' is ______ units.
- A 5
- B \(5 \sqrt{2}\)
- C \(5 \sqrt{3}\)
- D 10
Answer & Solution
Correct Answer
(C) \(5 \sqrt{3}\)
Step-by-step Solution
Detailed explanation
\(C_1: (x-2)^2 + (y+3)^2 = 2^2 + (-3)^2 - (-12) = 4+9+12 = 25\) Center of \(C_1 = (2, -3)\), Radius of \(C_1 = 5\)
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