MHT CET · Maths · Permutation Combination
If \(\frac{\mathrm{n} !}{2 !(\mathrm{n}-2) !}\) and \(\frac{\mathrm{n} !}{4 !(\mathrm{n}-4) !}\) are in the ratio \(2: 1\), then \(\mathrm{n}=\)
- A 6
- B 4
- C 5
- D 3
Answer & Solution
Correct Answer
(C) 5
Step-by-step Solution
Detailed explanation
We have \(\frac{n !}{2 !(n-2) !} \times \frac{4 !(n-4) !}{n !}=\frac{2}{1}\)
\(\therefore \frac{(4 \times 3)}{(n-2)(n-3)}=2 \Rightarrow n^2-5 n+6=6\)
\(\therefore \frac{(4 \times 3)}{(n-2)(n-3)}=2 \Rightarrow n^2-5 n+6=6\)
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