ExamBro
ExamBro
MHT CET · Maths · Permutation Combination

If \(\frac{\mathrm{n} !}{2 !(\mathrm{n}-2) !}\) and \(\frac{\mathrm{n} !}{4 !(\mathrm{n}-4) !}\) are in the ratio \(2: 1\), then \(\mathrm{n}=\)

  1. A 6
  2. B 4
  3. C 5
  4. D 3
Verified Solution

Answer & Solution

Correct Answer

(C) 5

Step-by-step Solution

Detailed explanation

We have \(\frac{n !}{2 !(n-2) !} \times \frac{4 !(n-4) !}{n !}=\frac{2}{1}\)
\(\therefore \frac{(4 \times 3)}{(n-2)(n-3)}=2 \Rightarrow n^2-5 n+6=6\)