MHT CET · Maths · Matrices
If matrix \(A=\left[\begin{array}{ll}a & b \\ c & d\end{array}\right]\), then \(|A|^{-1}\) is equal to
- A \(a d-b c\)
- B \(\frac{1}{a d-b c}\)
- C \(\frac{1}{a d-b c}\left[\begin{array}{rr}d & -b \\ -c & a\end{array}\right]\)
- D None of these
Answer & Solution
Correct Answer
(B) \(\frac{1}{a d-b c}\)
Step-by-step Solution
Detailed explanation
Given, \(\quad A=\left[\begin{array}{ll}a & b \\ c & d\end{array}\right]\)
\(
\begin{array}{l}
|A|=a d-b c \\
|A|^{-1}=\frac{1}{a d-b c}
\end{array}
\)
\(
\begin{array}{l}
|A|=a d-b c \\
|A|^{-1}=\frac{1}{a d-b c}
\end{array}
\)
See the Complete Solution
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