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MHT CET · Maths · Differential Equations

If \(\mathrm{m}\) is order and \(\mathrm{n}\) is degree of the differential equation \(\left(\frac{d^2 y}{d x^2}\right)^5+4 \frac{\left(\frac{d^2 y}{d x^2}\right)}{\left(\frac{d^3 y}{d x^3}\right)}+\left(\frac{d^3 y}{d x^3}\right)=x^2-1\), then

  1. A m=3, n=1
  2. B m=3, n=2
  3. C m=3, n=3
  4. D m=3, n=5
Verified Solution

Answer & Solution

Correct Answer

(B) m=3, n=2

Step-by-step Solution

Detailed explanation

\(\text {We have }\left(\frac{d^2 y}{d x^2}\right)^5+\frac{4\left(\frac{d^2 y}{d x^2}\right)}{\left(\frac{d^3 y}{d x^3}\right)}+\left(\frac{d^3 y}{d x^3}\right)=x^2-1\)
\(\therefore\left(\frac{d^3 y}{d x^3}\right)\left(\frac{d^2 y}{d x^2}\right)^5+4\left(\frac{d^2 y}{d x^2}\right)\left(\frac{d^3 y}{d x^3}\right)^2=\) \(\left(x^2-1\right)\left(\frac{d^3 y}{d x^3}\right)\)
\(\therefore \text { order }=3 \text {, degree }=2\)