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MHT CET · Maths · Differentiation

If log10x2-y2x2+y2=2, then dydx= _______

  1. A -99x101y
  2. B 99x101y
  3. C -99y101x
  4. D 99y101x
Verified Solution

Answer & Solution

Correct Answer

(A) -99x101y

Step-by-step Solution

Detailed explanation

Given, log10 x2-y2x2+y2=2
x2-y2x2+y2=100
x2-y2-100x2-100y2x2+y2=0
-99x2-101y2x2+y2=0
99x2+101y2=0
2×99x+2×101 ydydx=0
dydx=-99x101y