MHT CET · Maths · Matrices
If inverse of \(\left[\begin{array}{ccc}1 & 2 & x \\ 4 & -1 & 7 \\ 2 & 4 & -6\end{array}\right]\) does not exist, then \(x=\)
- A -3
- B 2
- C 3
- D 0
Answer & Solution
Correct Answer
(A) -3
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { Here }\left[\begin{array}{ccc}1 & 2 & x \\ 4 & -1 & 7 \\ 2 & 4 & -6\end{array}\right]=0 \\ & \therefore(6-28)-2(-24-14)+x(16+20)=0 \\ & \therefore-22+76+18 x=\Rightarrow x=-3\end{aligned}\)
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