MHT CET · Maths · Straight Lines
If \(\mathrm{G}(4,3,3)\) is the centroid of the triangle \(\mathrm{ABC}\) whose vertices are \(\mathrm{A}(\mathrm{a}, 3,1), \mathrm{B}(4,5, \mathrm{~b})\) and \(\mathrm{C}(6, \mathrm{c}, 5)\), then the value of \(\mathrm{a}, \mathrm{b}, \mathrm{c}\) are
- A \(a=1, b=2, c=3\)
- B \(a=3, b=2, c=1\)
- C \(a=2, b=1, c=3\)
- D \(\mathrm{a}=2, \mathrm{~b}=3, \mathrm{c}=1\)
Answer & Solution
Correct Answer
(D) \(\mathrm{a}=2, \mathrm{~b}=3, \mathrm{c}=1\)
Step-by-step Solution
Detailed explanation
We have vertices \(\mathrm{A}(\mathrm{a}, 3,1) ; \mathrm{B}(4,5, \mathrm{~b}) ; \mathrm{C}(6, \mathrm{c}, 5)\) and \(\mathrm{G}(4,3,3)\) of \(\triangle \mathrm{ABC}\)
\(
\frac{\mathrm{a}+4+6}{3}=4, \frac{3+5+\mathrm{c}}{3}=3, \frac{1+\mathrm{b}+5}{3}=3 \Rightarrow \)\(\mathrm{a}=2, \mathrm{c}=1, \mathrm{~b}=3
\)
\(
\frac{\mathrm{a}+4+6}{3}=4, \frac{3+5+\mathrm{c}}{3}=3, \frac{1+\mathrm{b}+5}{3}=3 \Rightarrow \)\(\mathrm{a}=2, \mathrm{c}=1, \mathrm{~b}=3
\)
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