MHT CET · Maths · Linear Programming
If feasible region is as shown in the figure, then related inequalities are
- A \(3 x+4 y \geq 12,4 x+7 y \leq 28, y \leq 1, x \geq 0, \ y \geq 0\)
- B \(3 x+4 y \geq 12,4 x+7 y \leq 28, y \geq 1, x \geq 0, \ y \geq 0\)
- C \(3 x+4 y \leq 12,4 x+7 y \leq 28, y \leq 1, x \geq 0, \ y \geq 0\)
- D \(3 x+4 y \leq 12,4 x+7 y \geq 28, y \geq 1, x \geq 0, \ y \geq 0\)
Answer & Solution
Correct Answer
(B) \(3 x+4 y \geq 12,4 x+7 y \leq 28, y \geq 1, x \geq 0, \ y \geq 0\)
Step-by-step Solution
Detailed explanation
Shaded region lies on origin side of \(4 x+7 y=28\) and above the line \(y=1\), and on non-origin side of \(3 x+4 y=12\).
\(\therefore 3 x+4 y \geq 12,4 x+7 y \leq 28, y \geq 1, x \geq 0, y \geq 0\)
\(\therefore 3 x+4 y \geq 12,4 x+7 y \leq 28, y \geq 1, x \geq 0, y \geq 0\)
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