MHT CET · Maths · Functions
If \(\mathrm{f}(x)=\cos (\log x)\) then
\(\mathrm{f}\left(x^2\right) \cdot \mathrm{f}\left(\mathrm{y}^2\right)-\frac{1}{2}\left[\mathrm{f}\left(\frac{x^2}{\mathrm{y}^2}\right)+\mathrm{f}\left(x^2 \mathrm{y}^2\right)\right]\) has the value
- A \(-2\)
- B \(-1\)
- C \(\frac{1}{2}\)
- D \(0\)
Answer & Solution
Correct Answer
(D) \(0\)
Step-by-step Solution
Detailed explanation
\(f(x^2) = \cos(2\log x)\) \(f(y^2) = \cos(2\log y)\)
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