MHT CET · Maths · Application of Derivatives
If \(\mathrm{f}(x)=x^3+\mathrm{b} x^2+\mathrm{c} x+\mathrm{d}\) and \(0 < \mathrm{b}^2 < \mathrm{c}\), then in \((-\infty, \infty)\)
- A \(\mathrm{f}(x)\) has a local maxima.
- B \(\mathrm{f}(x)\) is strictly increasing function.
- C \(\mathrm{f}(x)\) is bounded.
- D \(\mathrm{f}(x)\) is strictly decreasing function.
Answer & Solution
Correct Answer
(B) \(\mathrm{f}(x)\) is strictly increasing function.
Step-by-step Solution
Detailed explanation
\(\mathrm{f}(x)=x^3+\mathrm{b} x^2+\mathrm{c} x+\mathrm{d} \)
\( \therefore \mathrm{f}^{\prime}(x)=3 x^2+2 \mathrm{~b} x+\mathrm{c}\)
Now its discriminant \(=4\left(b^2-3 c\right)\) \(\Rightarrow 4\left(\mathrm{~b}^2-\mathrm{c}\right)-8 \mathrm{c} < 0\), as \(\mathrm{b}^2 < \mathrm{c}\) and \(\mathrm{c}>0\)
\(\Rightarrow \mathrm{f}^{\prime}(x)>0\) for all \(x \in \mathrm{R}\)
\(\Rightarrow f\) is strictly increasing on \(R\).
\( \therefore \mathrm{f}^{\prime}(x)=3 x^2+2 \mathrm{~b} x+\mathrm{c}\)
Now its discriminant \(=4\left(b^2-3 c\right)\) \(\Rightarrow 4\left(\mathrm{~b}^2-\mathrm{c}\right)-8 \mathrm{c} < 0\), as \(\mathrm{b}^2 < \mathrm{c}\) and \(\mathrm{c}>0\)
\(\Rightarrow \mathrm{f}^{\prime}(x)>0\) for all \(x \in \mathrm{R}\)
\(\Rightarrow f\) is strictly increasing on \(R\).
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