MHT CET · Maths · Limits
If \(\mathrm{f}(x)= \begin{cases}\frac{8^x-4^x-2^x+1}{x^2}, & \text { if } x>0 \\ \mathrm{e}^x \sin x+x+\lambda \log 4, & \text { if } x \leqslant 0\end{cases}\) is continuous at \(x=0\) then the value of \(1000 \mathrm{e}^\lambda=\)
- A \(1000\)
- B \(3000\)
- C \(2000\)
- D \(4000\)
Answer & Solution
Correct Answer
(C) \(2000\)
Step-by-step Solution
Detailed explanation
\(\lim_{x \to 0^+} f(x) = \lim_{x \to 0^+} \frac{8^x-4^x-2^x+1}{x^2}\) \( = \lim_{x \to 0^+} \frac{(4^x-1)(2^x-1)}{x^2} = \lim_{x \to 0^+} \left(\frac{4^x-1}{x}\right)\left(\frac{2^x-1}{x}\right) \)
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