MHT CET · Maths · Definite Integration
If \(\mathrm{f}(x)=\left\{\begin{array}{ll}\mathrm{e}^{\cos x} \sin x & , \text { for }|x| \leq 2 \ 2, & \text { otherwise }\end{array}\right.\), then \(\int_{-2}^3 \mathrm{f}(x) \mathrm{d} x\) is equal to
- A 0
- B 2
- C 1
- D 3
Answer & Solution
Correct Answer
(B) 2
Step-by-step Solution
Detailed explanation
\(\int_{-2}^3 \mathrm{f}(x) \mathrm{d} x =\int_{-2}^2 \mathrm{f}(x) \mathrm{d} x+\int_2^3 \mathrm{f}(x) \mathrm{d} x \)
\( =\int_{-2}^2 \mathrm{e}^{\cos x} \sin x \mathrm{~d} x+\int_2^3 2 \mathrm{~d} x\)
Since \(\mathrm{e}^{\cos x} \sin x\) is an odd function.
\(
\therefore \int_{-2}^3 \mathrm{f}(x) \mathrm{d} x=0+2(3-2)=2
\)
\( =\int_{-2}^2 \mathrm{e}^{\cos x} \sin x \mathrm{~d} x+\int_2^3 2 \mathrm{~d} x\)
Since \(\mathrm{e}^{\cos x} \sin x\) is an odd function.
\(
\therefore \int_{-2}^3 \mathrm{f}(x) \mathrm{d} x=0+2(3-2)=2
\)
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