MHT CET · Maths · Functions
If \(f(x)=\frac{3 x+4}{5 x-7}, x \neq \frac{7}{5}\)
\(g(x)=\frac{7 x+4}{5 x-3}, x \neq \frac{3}{5}\) then
\((g \circ f)(3)=\)
- A \(-3\)
- B \(-\frac{1}{3}\)
- C 3
- D \(\frac{1}{3}\)
Answer & Solution
Correct Answer
(C) 3
Step-by-step Solution
Detailed explanation
\(\therefore(g \circ f)(x) =g[f(x)] \)
\( =g\left[\frac{3 x+4}{5 x-7}\right] \)
\( =\frac{7\left(\frac{3 x+4}{5 x-7}\right)+4}{5\left(\frac{3 x+4}{5 x-7}\right)-3}=\frac{7(3 x+4)+4(5 x-7)}{5(3 x+4)-3(5 x-7)}=\frac{41 x}{41}=x \)
\( \therefore(g \circ f)(3) =3\)
\( =g\left[\frac{3 x+4}{5 x-7}\right] \)
\( =\frac{7\left(\frac{3 x+4}{5 x-7}\right)+4}{5\left(\frac{3 x+4}{5 x-7}\right)-3}=\frac{7(3 x+4)+4(5 x-7)}{5(3 x+4)-3(5 x-7)}=\frac{41 x}{41}=x \)
\( \therefore(g \circ f)(3) =3\)
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