MHT CET · Maths · Functions
If \(\mathrm{f}(\mathrm{x})=2\{\mathrm{x}\}+5 \mathrm{x}\), where \(\{\mathrm{x}\}\) is fractional part function, then \(f(-1.4)\) is
- A 8.2
- B -8.2
- C -5.8
- D -5
Answer & Solution
Correct Answer
(C) -5.8
Step-by-step Solution
Detailed explanation
We know that \(\mathrm{x}=[\mathrm{x}]+\{\mathrm{x}\}\)
When \(\mathrm{x}=-1.4\), we get \([\mathrm{x}]=-2\) and \(\{\mathrm{x}\}=0.6\)
We have \(f(x)=2\{x\}+5 x\)
\(\therefore \mathrm{f}(-1.4)=2(0.6)+5(-1.4)=-7+1.2=-5.8\)
When \(\mathrm{x}=-1.4\), we get \([\mathrm{x}]=-2\) and \(\{\mathrm{x}\}=0.6\)
We have \(f(x)=2\{x\}+5 x\)
\(\therefore \mathrm{f}(-1.4)=2(0.6)+5(-1.4)=-7+1.2=-5.8\)
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