MHT CET · Maths · Limits
If \(\mathrm{f}(x)=\frac{\sin \left(\pi \cos ^2 x\right)}{3 x^2}, x \neq 0\) is continuous at \(x=0\) then \(\mathrm{f}(0)=\)
- A 0
- B \(\frac{\pi}{3}\)
- C \(\frac{-\pi}{3}\)
- D \(\frac{3}{\pi}\)
Answer & Solution
Correct Answer
(B) \(\frac{\pi}{3}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{f}(0) = \lim_{x \to 0} \frac{\sin(\pi \cos^2 x)}{3x^2}\) \(\mathrm{f}(0) = \lim_{x \to 0} \frac{\sin(\pi (1-\sin^2 x))}{3x^2}\)
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