MHT CET · Maths · Functions
If \(f: R \rightarrow R\) be mapping defined by \(f(x)=x^{3}+5\), then \(f^{-1}(x)\) is equal to
- A \((x+5)^{1 / 3}\)
- B \((x-5)^{1 / 3}\)
- C \((5-x)^{1 / 3}\)
- D \(5-x\)
Answer & Solution
Correct Answer
(B) \((x-5)^{1 / 3}\)
Step-by-step Solution
Detailed explanation
Let
\(y=f(x)=x^{3}+5\)
\(\Rightarrow x=(y-5)^{1 / 3} \)
\( \therefore f^{-1}(x)=(x-5)^{1 / 3} \)
\( \text { Given, } f(x)=\frac{a x+b}{c x+d}\)
\(y=f(x)=x^{3}+5\)
\(\Rightarrow x=(y-5)^{1 / 3} \)
\( \therefore f^{-1}(x)=(x-5)^{1 / 3} \)
\( \text { Given, } f(x)=\frac{a x+b}{c x+d}\)
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