MHT CET · Maths · Differentiation
If \(\mathrm{f}(1)=3, \mathrm{f}^{\prime}(1)=2\), then \(\frac{\mathrm{d}}{\mathrm{d} x}\left\{\log \left[\mathrm{f}\left(\mathrm{e}^x+2 x\right)\right]\right\}\) at \(x=0\) is
- A \(\frac{2}{3}\)
- B \(\frac{3}{2}\)
- C \(2\)
- D \(0\)
Answer & Solution
Correct Answer
(C) \(2\)
Step-by-step Solution
Detailed explanation
\(\frac{\mathrm{d}}{\mathrm{d} x}\left\{\log \left[\mathrm{f}\left(\mathrm{e}^x+2 x\right)\right]\right\} = \\frac{1}{\mathrm{f}\left(\mathrm{e}^x+2 x\right)} \cdot \mathrm{f}^{\prime}\left(\mathrm{e}^x+2 x\right) \cdot (\mathrm{e}^x+2)\) At \(x=0\): \(\frac{1}{\mathrm{f}(1)} \cdot \mathrm{f}^{\prime}(1) \cdot (\mathrm{e}^0+2) = \frac{1}{3} \cdot 2 \cdot (1+2) = \frac{1}{3} \cdot 2 \cdot 3 = 2\)
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