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MHT CET · Maths · Ellipse

If \(e_{1}\) is the eccentricity of the ellipse \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1, a>b\) and \(e_{2}\) is the eccentricity
of the hyperbola \(\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1\), then \(e_{1}^{2}+e_{2}^{2}=\)

  1. A 2
  2. B 4
  3. C 1
  4. D 3
Verified Solution

Answer & Solution

Correct Answer

(A) 2

Step-by-step Solution

Detailed explanation

\(e_{1}=\sqrt{1-\frac{b^{2}}{a^{2}}} \quad e_{2}=\sqrt{1+\frac{b^{2}}{a^{2}}}\)
\(e_{1}^{2}+e_{2}^{2}=2\)