MHT CET · Maths · Ellipse
If \(e_{1}\) is the eccentricity of the ellipse \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1, a>b\) and \(e_{2}\) is the eccentricity
of the hyperbola \(\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1\), then \(e_{1}^{2}+e_{2}^{2}=\)
- A 2
- B 4
- C 1
- D 3
Answer & Solution
Correct Answer
(A) 2
Step-by-step Solution
Detailed explanation
\(e_{1}=\sqrt{1-\frac{b^{2}}{a^{2}}} \quad e_{2}=\sqrt{1+\frac{b^{2}}{a^{2}}}\)
\(e_{1}^{2}+e_{2}^{2}=2\)
\(e_{1}^{2}+e_{2}^{2}=2\)
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