MHT CET · Maths · Trigonometric Equations
If \(\operatorname{cosec} \theta+\cot \theta=5\), then \(\sin \theta=\)
- A \(\frac{1}{5}\)
- B \(\frac{5}{26}\)
- C \(\frac{5}{13}\)
- D \(\frac{1}{13}\)
Answer & Solution
Correct Answer
(C) \(\frac{5}{13}\)
Step-by-step Solution
Detailed explanation
Given \(\operatorname{cosec} \theta+\cot \theta=5\)
We know that \(\operatorname{cosec}^{2} \theta-\cot ^{2} \theta=1\)
\(\Rightarrow(\operatorname{cosec} \theta-\cot \theta)(\operatorname{cosec} \theta+\cot \theta)=1 \Rightarrow \operatorname{cosec} \theta-\cot \) \(\theta=\frac{1}{5}\)
Adding (1) \& (2), we get
\(2 \operatorname{cosec} \theta=5+\frac{1}{5}=\frac{26}{5}\)
\(\therefore \operatorname{cosec} \theta=\frac{13}{5} \Rightarrow \sin \theta=\frac{5}{13}\)
We know that \(\operatorname{cosec}^{2} \theta-\cot ^{2} \theta=1\)
\(\Rightarrow(\operatorname{cosec} \theta-\cot \theta)(\operatorname{cosec} \theta+\cot \theta)=1 \Rightarrow \operatorname{cosec} \theta-\cot \) \(\theta=\frac{1}{5}\)
Adding (1) \& (2), we get
\(2 \operatorname{cosec} \theta=5+\frac{1}{5}=\frac{26}{5}\)
\(\therefore \operatorname{cosec} \theta=\frac{13}{5} \Rightarrow \sin \theta=\frac{5}{13}\)
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