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MHT CET · Maths · Matrices

If \(B=\left[\begin{array}{ccc}3 & \alpha & -1 \\ 1 & 3 & 1 \\ -1 & 1 & 3\end{array}\right]\) is the adjoint of \(a\) \(3 \times 3\) matrix \(\mathrm{A}\) and \(|\mathrm{A}|=4\), then \(\alpha\) is equal to8

  1. A \(1\)
  2. B \(0\)
  3. C \(-1\)
  4. D \(-2\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(1\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned}
& \quad \text { Using }|\operatorname{adj} A|=|A|^{\mathrm{n}-1} \\
& \quad \text { But } \mathrm{B}=\operatorname{Adj}(\mathrm{A}) ...[Given]\\
& \therefore \quad|\mathrm{B}|=|\mathrm{A}|^2 \\
& \Rightarrow\left|\begin{array}{ccc}
3 & \alpha & -1 \\
1 & 3 & 1 \\
-1 & 1 & 3
\end{array}\right|=|\mathrm{A}|^2 \\
& \Rightarrow 24-4 \alpha-4=4^2 \\
& \Rightarrow 20-4 \alpha=16 \\
& \Rightarrow \alpha=1
\end{aligned}\)