MHT CET · Maths · Determinants
If \(\left[\begin{array}{lll}1 & 3 & 3 \\ 1 & 4 & 4 \\ 1 & 3 & 4\end{array}\right]\left[\begin{array}{l}x \\ y \\ z\end{array}\right]=\left[\begin{array}{l}12 \\ 15 \\ 13\end{array}\right]\), then the value of \(x^2+y^2+z^2=\)
- A \(6\)
- B \(12\)
- C \(3\)
- D \(14\)
Answer & Solution
Correct Answer
(D) \(14\)
Step-by-step Solution
Detailed explanation
\( (x+4y+4z) - (x+3y+3z) = 15-12 \Rightarrow y+z=3 \) \( (x+3y+4z) - (x+3y+3z) = 13-12 \Rightarrow z=1 \)
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