MHT CET · Maths · Vector Algebra
If \(\vec{a}=\hat{i}-\hat{k}, \vec{b}=x \hat{i}+\hat{j}+(1-x) \hat{k} \quad\) and \(\quad \vec{c}=y \hat{i}+x \hat{j}+(1+x-y) \hat{k}\) then \([\vec{a} \vec{b} \vec{c}]\) depends on
- A neither \(x\) nor \(y\)
- B only \(x\)
- C only \(y\)
- D both \(x\) and \(y\)
Answer & Solution
Correct Answer
(A) neither \(x\) nor \(y\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & {[\vec{a} \vec{b} \vec{c}]=\left|\begin{array}{ccc}1 & 0 & -1 \\ x & 1 & 1-x \\ y & x & 1+x-y\end{array}\right|=\left|\begin{array}{ccc}0 & 0 & -1 \\ 1 & 1 & 1-x \\ 1+x & x & 1+x-y\end{array}\right|} \\ & =-1(x-1-x) \\ & =1 \text { which is independent of both } x \text { and } y\end{aligned}\)
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