MHT CET · Maths · Vector Algebra
If \(\bar{a}=\hat{i}+\hat{j}+\hat{k}, \bar{b}=\hat{i}-\hat{j}+2 \hat{k}, \bar{c}=x \hat{i}+(x-2) \hat{j}-\hat{k}\) and \(\bar{c}\) is linear combination of \(\bar{a}\) and \(\bar{b}\), then \(x\) has the value
- A 1
- B -2
- C 0
- D -4
Answer & Solution
Correct Answer
(B) -2
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \vec{c}=\vec{b}+\lambda \vec{a} \\ & \Rightarrow x \hat{i}+(x-2) \hat{j}-\widehat{k}=(\hat{i}-\hat{j}+2 \widehat{k})+\lambda(\hat{i}+\hat{j}+\widehat{k}) \\ & \Rightarrow x=1+\lambda, x-2=-1+\lambda \text { and }-1=2+\lambda \\ & \Rightarrow \lambda=-3 \text { and } x=-2\end{aligned}\)
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